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11. In rhombus MATH, MS = 6 and SA = 8. Find the perimeter of the rhombus.

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11. In rhombus MATH, MS = 6 and SA = 8. Find the perimeter of the rhombus. M А 8 A-example-1
User Sublimemm
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1 Answer

9 votes

Answer:

40

Explanation:

A rhombus diagonals form perpendicular angles. It also bisects and form 4 right triangles. Looking at triangle MAS, we can use pythagorean theorem to find the side MA.


ms {}^(2) + sa {}^(2) = {ma}^(2)

ms=6, sa =8 so we plug that in.


6 {}^(2) + {8}^(2) = ma {}^(2)

Simplify


36 + 64 = ma {}^(2)


100 = ma {}^(2)

take sqr root


√(100) = ma


ma = 10

Now let find the perimeter

Since perimeter of a Rhombus is 4a where a is the length of a side. We plug it in


4(10) = 40

The answer is 40

User PabloDK
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