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You have 2.2 mol xe and 3.7 mol f², but when you carry out the reaction you end up with only 0.25 mol xef⁴. what is the perce yield of this experiment? xe(g) +2 f² (g) > xef⁴ (g)

User Zeehio
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Final answer:

The percent yield of the experiment is 100%

Step-by-step explanation:

The percent yield of a reaction can be calculated using the formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

In this case, the actual yield is given as 0.25 mol and the balanced equation tells us that the stoichiometric ratio between Xe and XeF4 is 1:1. Therefore, the theoretical yield would also be 0.25 mol.

Using the formula, we can calculate the percent yield:

Percent Yield = (0.25 mol / 0.25 mol) x 100% = 100%

User Thastark
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