Final answer:
The function f(x) = x^3 + 9x has one real zero at x = 0 and two imaginary zeros at x = ±3i, which means the correct answer is b. Zeros: x = 0, Imaginary zeros: x = ±3i.
Step-by-step explanation:
To find the zeros and imaginary zeros of the function f(x) = x^3 + 9x, we will first factor out what's common, which is x. This gives us:
f(x) = x(x^2 + 9)
We can easily see that x = 0 is a zero of the function. We then set the other factor equal to zero to find the remaining zeros:
x^2 + 9 = 0
Solving for x, we get:
x^2 = -9
x = ±√(-9)
x = ±3i
Therefore, we have one real zero at x = 0 and two imaginary zeros at x = ±3i.
So the correct answer is b. Zeros: x = 0, Imaginary zeros: x = ±3i.