132k views
4 votes
Derive the cofunction identity:

a) sin(-x) = cos(90° - x)
a) cos(1) cos(x)
b) cos(x) - sin(x)
c) cos(x) - sin(90° - x)
d) cos(x) + sin(x)

User Yogi
by
8.1k points

1 Answer

6 votes

Final answer:

To derive the cofunction identity sin(-x) = cos(90° - x), we can start by rewriting sin(-x) as -sin(x). Then, we use the identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b) and plug in the values to simplify and prove the cofunction identity.

Step-by-step explanation:

To derive the cofunction identity, let's start with the given equation sin(-x) = cos(90° - x). We know that sin(-x) is equal to -sin(x), so we can rewrite the equation as -sin(x) = cos(90° - x). Now, we can use the identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b). Let a = 90° and b = -x. Plugging in these values, we have -sin(x) = sin(90°)cos(-x) + cos(90°)sin(-x). Since sin(90°) = 1 and cos(90°) = 0, the equation simplifies to -sin(x) = 0 cos(-x) + 1 sin(-x). Simplifying further, we get -sin(x) = sin(-x), which proves the cofunction identity.

User Richard Downer
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories