Question

If you mix 45.01 grams of sodium bicarbonate with 62.54 grams of hydrogen acetate, how much water would you expect to make?

(a) 9.94 grams
(b) 28.16 grams
(c) 56.32 grams
(d) 84.48 grams

Answer 1

To calculate the amount of water produced when sodium bicarbonate and hydrogen acetate react, we can use the balanced chemical equation and the molar mass of sodium bicarbonate.

Step-by-step explanation:

To calculate the amount of water produced when sodium bicarbonate and hydrogen acetate react, we need to consider the balanced chemical equation for the reaction. Given the equation:

2NaHCO3 + 2CH3CO2H → 2CH3CO2Na + CO2 + 2H2O

We can see that for every 2 moles of sodium bicarbonate, 2 moles of water are produced. So, if we have 45.01 grams of sodium bicarbonate, we can calculate the amount of water using the molar mass of sodium bicarbonate:

(45.01 g NaHCO3) / (84.007 g/mol NaHCO3) x (2 mol H2O / 2 mol NaHCO3) x (18.015 g/mol H2O) = 19.02 grams of water

Therefore, the correct answer is (a) 9.94 grams of water.