Final answer:
Hexane could hold approximately 40,000,000 droplets before it spilled over.
Step-by-step explanation:
Hexane is a liquid with a known density of approximately 0.6607 g/mL. To determine how many droplets it can hold before spilling over, we need to know how much volume each droplet occupies.
Let's assume that each droplet has a volume of 0.01 mL.
Therefore, we can calculate the number of droplets hexane can hold by dividing the total volume of hexane by the volume of each droplet:
Volume of hexane = 400 liters = 400,000 mL
Number of droplets = Volume of hexane / Volume of each droplet = 400,000 mL / 0.01 mL = 40,000,000 droplets
Therefore, hexane could hold approximately 40,000,000 droplets before it spilled over.