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What will happen when an object of 0.8 g/cm³ and an object of 1.2 g/cm³ are placed on a container of water?

A) Both objects will sink.
B) Both objects will float.
C) The object with a density of 0.8 g/cm³ will sink, while the object with a density of 1.2 g/cm³ will float.
D) The object with a density of 0.8 g/cm³ will float, while the object with a density of 1.2 g/cm³ will sink.

User Yousef
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Final answer:

An object with a density of 0.8 g/cm³ will float in water because it's less dense than water, while an object with a density of 1.2 g/cm³ will sink because it's denser than water.

Step-by-step explanation:

When objects are placed in water, whether they float or sink is determined by their density in comparison to the density of water. Water at 4°C has a density of approximately 1 g/cm³. An object with a density of 0.8 g/cm³ is less dense than water, therefore it will float due to the buoyant force being greater than the object's weight. Conversely, an object with a density of 1.2 g/cm³ is denser than water, meaning it will sink because its weight is greater than the buoyant force exerted by the water.

Therefore, when an object of 0.8 g/cm³ and an object of 1.2 g/cm³ are placed on a container of water, the object with a density of 0.8 g/cm³ will float, while the object with a density of 1.2 g/cm³ will sink. This is in accordance with the Archimedes' principle, which relates the buoyant force to the weight of the fluid displaced by an object.

User Paulo Bueno
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