Question

Given t(x) = - 4.9t^2 + 3t + 10, what is the value of t(1)?

a) -0.4
b) 0.6
c) 1.4
d) 2.6

Answer 1

To calculate t(1), substitute 1 into the equation, resulting in t(1) = -4.9 + 13, which simplifies to 8.1. The answer doesn't match any of the given options, suggesting there might be an error in the question or options provided.

The correct answer is none of all.

Step-by-step explanation:

To find the value of t(1), you simply need to substitute 1 for t in the equation given: t(x) = - 4.9t^2 + 3t + 10. So when t equals 1, the equation becomes t(1) = - 4.9(1)^2 + 3(1) + 10.

Perform the calculations step-by-step:

1. Calculate the square of 1: (1)^2 = 1.
2. Multiply this by -4.9: -4.9 × 1 = -4.9.
3. Multiply 3 by 1: 3 × 1 = 3.
4. Add these values together with 10: (-4.9) + 3 + 10.
5. The result is t(1) = -4.9 + 13, which simplifies to t(1) = 8.1.

However, the result is not listed among the options provided in the question. It seems there might be an error in the question or the given options. Please recheck the equation and the provided options.