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Find the solution point for the following equations using the elimination method:

-4 + 3 = -12
-2x + y = 6

1 Answer

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Given :

  • Two linear equations in two variables .
  1. -4x +3y = -12
  2. -2x + y = 6

To Find :

  • The solution of the equation by elimination method .

Solution :

Multiplying the 2nd equation with 2 , we have ,

→ 2(-2x + y) = 6*2

→ -4x + 2y = 12 . . . . . (3)

Subtracting equations 1 and 3 , we have ,

→ -4x +3y -(-4x + 2y) = -12-12

→ -4x + 3y + 4x - 2y = -24

→ y = -24

Substituting the value in equation 1 ,

→ -4x + 3(-24) = -12

→ -4x - 72 = -12

→ -4x = 72-12

→ -4x = 60

→ x = 60/-4

→ x = -15

Hence the solution point is (x,y) = (-15,-24).

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