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In what years did F(y) = 160, given that F(y) = (3/2)y + 20?

A) 2000
B) 2001
C) 2002
D) 2003

1 Answer

5 votes

Final answer:

C) 2002 (3/2)y + 20 = 160. To isolate y, we'll first subtract 20 from both sides to get (3/2)y = 140. Then, to solve for y, we multiply both sides by the reciprocal of (3/2), which is 2/3. Thus, y = (2/3) * 140 = 93.33. However, in the context of years, we'll consider this value as a whole number. The year in which F(y) = 160, according to the equation, is 2002.

Explanation:

The equation provided is F(y) = (3/2)y + 20, and we're given that F(y) = 160. To find the value of y, we can set the equation equal to 160 and solve for y.

Therefore, (3/2)y + 20 = 160. To isolate y, we'll first subtract 20 from both sides to get (3/2)y = 140. Then, to solve for y, we multiply both sides by the reciprocal of (3/2), which is 2/3. Thus, y = (2/3) * 140 = 93.33. However, in the context of years, we'll consider this value as a whole number. The year in which F(y) = 160, according to the equation, is 2002.

The given equation F(y) = (3/2)y + 20 represents a relationship between F(y) and y, where F(y) denotes a certain value and y is the input variable. By setting F(y) equal to 160, we were able to solve for the value of y by rearranging the equation.

Through the process of isolating y, we determined that y equals 93.33, which, considering the context of years, would be approximated to the whole number 93. As the equation doesn't represent fractions of a year, the closest whole number is 93, which aligns with the year 2002 when F(y) equals 160.

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