Final answer:
The equation of the line passing through the points (6, -10) and (3, -15) is y = (5/3)x - 20.
Step-by-step explanation:
To find the equation of the line passing through the points (6, -10) and (3, -15), we can use the formula y = mx + b, where m is the slope and b is the y-intercept.
First, we need to find the slope (m) of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates of the given points:
m = (-15 - (-10)) / (3 - 6) = (-5) / (-3) = 5/3
Next, we need to find the y-intercept (b) using one of the points and the slope:
Using the point (6, -10):
-10 = (5/3) * 6 + b
Simplifying:
-10 = 10 + b
b = -10 - 10 = -20
Therefore, the equation of the line passing through the points (6, -10) and (3, -15) is:
y = (5/3)x - 20.