Question

A golf club exerts an average force of 1000 N on a 0.045-kg golf ball which is initially at rest. The club is in contact with the ball for 1.8 ms. What is the speed of the golf ball as it leaves the tee (in m/s)?

Answer 1

The speed of the golf ball as it leaves the tee is 40 m/s.

Step-by-step explanation:

To calculate the speed of the golf ball as it leaves the tee, we can use the principle of impulse and momentum. Impulse is the product of force and time, and for a constant force, it is equal to the change in momentum. In this case, the average force exerted by the golf club is 1000 N and the time of contact is 1.8 ms.

Using the formula for impulse, we can calculate the change in momentum of the golf ball:

Impulse = Force × time = change in momentum

(1000 N) × (1.8 ms) = (0.045 kg) × v_f

Where v_f is the final velocity of the golf ball.

Simplifying the equation, we have:

v_f = (1000 N × 1.8 ms) / 0.045 kg = 40 m/s

Therefore, the speed of the golf ball as it leaves the tee is 40 m/s.