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"Which equation is the slope-intercept form of the line that passes through (12, 9) and is perpendicular to the graph of y = −34x + 1?

A. y = 43x – 7
B. y = –34x – 6"

1 Answer

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Final answer:

The equation representing the slope-intercept form of a line passing through (12, 9) and perpendicular to y = -34x + 1 is y = (1/34)x - 11/17.

Step-by-step explanation:

The equation that represents the slope-intercept form of a line passing through the point (12, 9) and perpendicular to the graph of y = -34x + 1 can be found by considering that the slope of a perpendicular line is the negative reciprocal of the original slope.

Given that the original line has a slope of -34, the perpendicular line will have a slope of 1/34. Using the point-slope form of a line, we have y - 9 = (1/34)(x - 12). By rearranging this equation, we can obtain the slope-intercept form: y = (1/34)x - 11/17.

Therefore, the correct answer is option A: y = (1/34)x - 11/17.

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