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a three-phase load has a phase voltage of 240 v and a phase current of 18 a. if the load in the circuit above is connected to a wye, what would be the line voltage and line current supplying the load?

User Klinore
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For a wye-connected load with 240V phase voltage and 18A phase current: line voltage is 415.5V, line current remains 18A (balanced system assumed).

The line voltage and line current can be calculated using the following steps:

1. Phase voltage to line voltage relationship:

In a wye (star) connection, the line voltage is √3 times the phase voltage. Therefore, the line voltage (VL) in this case is:

VL = √3 * VP = √3 * 240 V ≈ 415.5 V

2. Phase current to line current relationship:

In a balanced three-phase system, the line current (IL) is equal to the phase current (IP). Therefore, the line current in this case is:

IL = IP = 18 A

Therefore, the line voltage and line current supplying the load are:

Line voltage (VL): 415.5 V

Line current (IL): 18 A

It's important to note that this is only true for a balanced three-phase system. If the load is unbalanced, the calculations would be more complex and require additional information about the phase impedances.

User Roy Riojas
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