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Classify by the degree and number of terms.
6(x²-3x+1)-(x³-18x)-6

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Final answer:

The given expression is classified as having a term of degree 3, two terms of degree 2, and two terms of degree 0.

Step-by-step explanation:

The given expression is 6(x²-3x+1)-(x³-18x)-6.

Let's classify this expression by the degree and number of terms:

The degree of a term is the sum of the exponents of all its variables. In the given expression:

  • The highest degree of x is 3, which occurs in the term x³.
  • There are 3 terms in the expression: x²-3x+1, -(x³-18x), and -6.

Therefore, the given expression has:

  • A term of degree 3: x³
  • Two terms of degree 2: x² and -(x³-18x)
  • Two terms of degree 0: 1 and -6

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