Question

A magnetic field is oriented at an angle of 44∘ to the normal of a rectangular area 6.5 cm by 6.8 cm If the magnetic fux through this surface has a magnitude of 4.3×10⁻⁵T⋅m2, what is the strength of the magnetic field? Express your answer using two significant figures.

Answer 1

To find the strength of the magnetic field, divide the magnetic flux by the product of the area and the cosine of the angle. Using the given values, the strength of the magnetic field is approximately 2.4 × 10⁻⁴ T.

Step-by-step explanation:

To find the strength of the magnetic field, we can use the formula:

magnetic field strength = magnetic flux / (area * cos(angle))

Given:
area = 6.5 cm * 6.8 cm = 44.2 cm²
magnetic flux = 4.3 × 10⁻⁵ T⋅m²
angle = 44°

Converting the area to square meters: area = 0.442 m²

Using the formula:

magnetic field strength = 4.3 × 10⁻⁵ T⋅m² / (0.442 m² * cos(44°))

Calculating the value:

magnetic field strength ≈ 2.42 × 10⁻⁴ T

Therefore, the strength of the magnetic field is approximately 2.4 × 10⁻⁴ T.