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What is approximately the frequency of an EM wave that has an electric field component given by the following expression:

E=2000 NCsin((3.8 x 1015 rad/s)t-(1.3 x 10⁷rad/m)x)

a) 8.2 x 10⁷ Hz

b) 2.4 x 10¹⁶ Hz

c) 1.3 x 10⁷ Hz

d) 3.8 x 10¹⁵ Hz

e) 2000 Hz

User Carmina
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1 Answer

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Final answer:

The frequency of the electromagnetic wave is approximately 6.05 x 10^14 Hz.

Step-by-step explanation:

The question provides the expression for the electric field component of an electromagnetic wave: E = 2000 N/C * sin((3.8 x 10^15 rad/s)t - (1.3 x 10^7 rad/m)x). To find the frequency of the wave, we can focus on the term inside the sine function, which represents the angular frequency of the wave. In this case, the angular frequency is given by 3.8 x 10^15 rad/s. The frequency of an electromagnetic wave can be obtained by dividing the angular frequency by 2π. Therefore, the frequency of this wave is approximately equal to 3.8 x 10^15 rad/s divided by 2π, which is approximately equal to 6.05 x 10^14 Hz.

User KolA
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