Final answer:
The maximum voltage across the 130-Ω resistor is 3120 V, and the rms current through the resistor is 16.97 A.
Step-by-step explanation:
To find the maximum voltage across the resistor, we can use Ohm's Law, which states that Voltage (V) is equal to the product of Current (I) and Resistance (R). In this case, the peak-to-peak current passing through the resistor is given as 24.0 A and the resistance is 130 Ω. So, the maximum voltage across the resistor is:
V = I * R
V = 24.0 A * 130 Ω
V = 3120 V
To find the rms current through the resistor, we need to divide the peak-to-peak current by √2 (the square root of 2) since the peak-to-peak current is the maximum current and the rms current is the effective current or the root mean square current. So, the rms current can be calculated as:
Irms = Ipeak-to-peak / √2
Irms = 24.0 A / √2
Irms = 16.97 A