Final answer:
The heat energy absorbed by 25.0 grams of water when its temperature increases from 24.0°C to 36.0°C is calculated using the formula q = mc∆T with a specific heat capacity for water of 4.184 J/g°C. However, the calculated result of 1254.40 J does not match any of the provided multiple-choice answers.
Step-by-step explanation:
The total amount of heat energy absorbed by water when its temperature increases can be calculated using the specific heat formula: q = mc∆T, where q is the heat energy in joules, m is the mass of the water in grams, c is the specific heat capacity of water (which is 4.184 J/g°C for water), and ∆T is the change in temperature in degrees Celsius.
In this case, we are looking for the heat energy absorbed by 25.0 grams of water when its temperature increases from 24.0°C to 36.0°C. The temperature change (∆T) is 36.0°C - 24.0°C = 12.0°C. So, we calculate the heat energy absorbed as follows:
q = (25.0 g) × (4.184 J/g°C) × (12.0°C)
q = 1254.40 J
This result is not an option provided in the multiple-choice answers, indicating that there might be a mistake. Please double-check the calculation or the given options.