Question

You push a box at a constant speed of 5m/s and let it go. It stops 1.5s later due to the force of friction. If you push the box at a speed of 12m/s, how long will it take to stop?

Answer 1

the time taken for the box to stop is 3.6 s.

Step-by-step explanation:

Given;

initial speed with which the box was pushed, u = 5 m/s

time taken for the box to stop, t = 1.5 s

Assuming the box is moving at constant acceleration, a;

`a = (u)/(t) \\\\a = (5)/(1.5) \\\\a = 3.33 \ m/s`

When the box is pushed a speed of 12 m/s, the time taken for the box to stop is calculated as;

`t = (v)/(a) \\\\t = (12)/(3.33) \\\\t = 3.6 \ s`

Therefore, the time taken for the box to stop is 3.6 s.