The energy, in joules, is produced in this reaction is 1.8E-12 J.
To calculate the energy released in the deuterium-tritium fusion reaction, we can use the following equation:
E = mc^2
where:
E is the energy released in joules
m is the mass difference between the initial and final particles in kilograms
c is the speed of light in meters per second
The mass difference in this reaction is:
(3.34 + 5.01) × 10^(-27) kg - (6.64 + 1.67) × 10^(-27) kg = 1.69 × 10^(-27) kg
Therefore, the energy released in the reaction is:
E = (1.69 × 10^(-27) kg) × (2.998 × 10^8 m/s)^2 = 1.76 × 10^(-12) J
To one decimal place, this is 1.8E-12 J.
Therefore, the answer to the question is 1.8E-12.
This represents the conversion of a small amount of mass into a substantial amount of energy, as described by Einstein's famous equation.