Question

if an additional 0.197 mol of gas is added to the balloon (at constant temperature and pressure), what is its final volume? express your answer in liters to three significant figures.

Answer 1

Using Avogadro's Law, the final volume of the gas in the balloon when 0.197 mol is added to the initial amount is calculated to be 5.97 L when rounded to three significant figures.

Step-by-step explanation:

To determine the final volume of a gas in a balloon when additional gas is added, we use the direct proportion relationship between the amount of gas (in moles) and volume when temperature and pressure are constant (Avogadro's Law).

From the given information, we know that initially 0.0920 mol of helium gas occupies 1.90 L. Now, if 0.197 mol of gas is added, making the total number of moles 0.0920 mol + 0.197 mol = 0.289 mol, we can calculate the new volume using the proportion:

V1/n1 = V2/n2, where V1 = 1.90 L and n1 = 0.0920 mol.

Therefore:

V2 = (V1 * n2) / n1 = (1.90 L * 0.289 mol) / 0.0920 mol = 5.965 L

So, the final volume will be 5.97 L, rounding to three significant figures.