Question

Not surprisingly, Mr. Sul loves to slide around in his socks when the classroom floor has been freshly waxed. Mr. Sul has a weight of 800N and the coefficient of kinetic friction between his socks and the floor is 0.30. How strong is the Friction Force that opposes his sliding?

Answer 1

The Friction Force that opposes Mr. Sul's sliding is calculated using the formula for kinetic friction, and with a coefficient of 0.30 and a normal force of 800 N, the friction force is 240 N.

Step-by-step explanation:

The Friction Force that opposes Mr. Sul's sliding can be calculated using the formula for kinetic friction, which is f_k = μ_k × N, where f_k is the kinetic friction force, μ_k is the coefficient of kinetic friction, and N is the normal force. Given the weight (W) of Mr. Sul is 800 N and the coefficient of kinetic friction (μ_k) is 0.30, we first need to establish that the normal force (N) is equal to his weight because he is on a horizontal surface, so N = W = 800 N. Applying the formula, we get f_k = 0.30 × 800 N = 240 N. Therefore, the friction force opposing his sliding is 240 N.