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What point on the line y=7x+10 is closest to the origin?

A) (-2, 4)
B) (-1, 3)
C) (0, 10)
D) (1, 17)

User NextInLine
by
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1 Answer

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Final Answer:

The point on the line y = 7x + 10 closest to the origin is option B) (-1, 3).

Step-by-step explanation:

To find the point on the line closest to the origin, we can use the distance formula
\(d = √((x_2 - x_1)^2 + (y_2 - y_1)^2)\) . In this case, the coordinates of the origin are O(0, 0), and we need to find the distance from O to each of the given points.

Let's calculate the distances:

1. For point A (-2, 4):
\(d_A = √((-2 - 0)^2 + (4 - 0)^2) = √(4 + 16) = √(20)\).

2. For point B (-1, 3):
\(d_B = √((-1 - 0)^2 + (3 - 0)^2) = √(1 + 9) = √(10)\).

3. For point C (0, 10):
\(d_C = √((0 - 0)^2 + (10 - 0)^2) = √(100) = 10\).

4. For point D (1, 17):
\(d_D = √((1 - 0)^2 + (17 - 0)^2) = √(1 + 289) = √(290)\).

The smallest distance is
\(√(10)\), which corresponds to option B (-1, 3). Therefore, the point (b)(-1, 3) on the line y = 7x + 10 is closest to the origin.

User SeeTheC
by
7.4k points

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