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How many positive integers n satisfy the following condition: (130n)⁵>n¹00>200.

User Lynnann
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Final answer:

To solve the inequality (130n)⁵ > n¹00 > 200 for positive integers n, we can simplify the expression and solve the resulting inequality step-by-step.

Step-by-step explanation:

In order to solve the inequality (130n)⁵ > n¹00 > 200, we need to find the range of values for positive integers n that satisfy the condition. Let's break it down step-by-step:

  1. Start by simplifying the expression (130n)⁵. This can be rewritten as (130⁵)(n⁵) since powers distribute over multiplication.
  2. Next, simplify further by calculating (130⁵) to get a constant value.
  3. Now, we have (constant)(n⁵) > n¹00 > 200. Since we want to find positive integers n, we can divide both sides of the inequality by n⁵.
  4. This gives us a new inequality: (constant) > (n¹00/n⁵) > (200/n⁵).
  5. Finally, we can simplify and solve this inequality to find the range of values for n.

User Kiminoa
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