2x^2-20x=x^(2) -19

Question

`2x^2-20x=x^(2) -19`

Answer 1

x1 = 1 x2 = 19 if I’m correct

Answer 2

x = 1, x = 19

Explanation:

Given

2x² - 20x = x² - 19 ( subtract x² - 19 from both sides )

x² - 20x + 19 = 0 ← in standard form

(x - 1)(x - 19) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 19 = 0 ⇒ x = 19