Final answer:
When an alkyl halide is treated with NaOH, the product formed is an alcohol.
Step-by-step explanation:
When an alkyl halide is treated with NaOH, the product formed is an alcohol. This is because the inorganic hydroxide base reacts with the alkyl halide to form an alkoxide ion, which then reacts with water to produce the alcohol.
For example, if you have an alkyl halide like methyl bromide (CH3Br) and you treat it with NaOH, the product formed will be methanol (CH3OH).
Overall reaction:
CH3Br + NaOH → CH3OH + NaBr