Final answer:
The zeros of the function h(x) = 4x^2 + 36 are ±3i.
Step-by-step explanation:
The zeros of the function h(x) = 4x^2 + 36 can be found by setting the function equal to zero and solving for x.
4x^2 + 36 = 0
Subtracting 36 from both sides, we get:
4x^2 = -36
Dividing both sides by 4, we get:
x^2 = -9
Taking the square root of both sides, we get:
x = ±3i
Therefore, the zeros of the function h(x) = 4x^2 + 36 are ±3i.