Question

H(x)=4x^2+36
the zeros of the function are

Answer 1

The zeros of the function h(x) = 4x^2 + 36 are ±3i.

Step-by-step explanation:

The zeros of the function h(x) = 4x^2 + 36 can be found by setting the function equal to zero and solving for x.

4x^2 + 36 = 0

Subtracting 36 from both sides, we get:

4x^2 = -36

Dividing both sides by 4, we get:

x^2 = -9

Taking the square root of both sides, we get:

x = ±3i

Therefore, the zeros of the function h(x) = 4x^2 + 36 are ±3i.