Solve for x. If not solution, type no solution. a. 15x - 3|= 12 X= X= b. lx + 8) = 2 X= X= c. |x-41 = -5 X= X=

Nikravi asked Dec 23, 2023

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6 votes

Solve for x. If not solution, type no solution.

a. 15x - 3|= 12
X=
X=

b. lx + 8) = 2
X=
X=

c. |x-41 = -5
X=
X=

Nikravi asked Dec 23, 2023

3.1k points

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14 votes

Part a

$|5x-3|=12\\\\5x-3=\pm 12\\\\5x=3 \pm 12\\ \\ 5x=-9, 15\\\\x=-(9)/(5), 3$

Part b

$|x+8|=2\\\\x+8=\pm 2\\\\x=-8 \pm 2\\\\x=-10, -6$

Part c

The equation has no solutions because the absolute value function provides non-negative outputs.

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