87.4k views
3 votes
Use bond energies to calculate the enthalpy of combustion of one mole of methanol in kj per mole methanol. 2CH₃OH + 3O₂--> 2co₂ 4H₂

a) −1452kJ/mol
b) -1458kJ/mol
c) −1464kJ/mol
d) −1470kJ/mol

1 Answer

0 votes

Final answer:

The question involves calculating the enthalpy of combustion of methanol using bond energies. Exact bond energy values are needed to perform the calculation, which will give an approximate result due to the nature of bond energy estimations.

Step-by-step explanation:

The student is asking to calculate the enthalpy of combustion of one mole of methanol (CH3OH). The enthalpy of a reaction can be found using bond energies, which are the energies required to break or form chemical bonds. For the combustion of methanol, we need to consider the breaking of bonds in CH3OH and O2, and the formation of bonds in CO2 and H2O.

To solve this problem, we would use the formula:

ΔH = ∑ Energy of bonds broken - ∑ Energy of bonds formed

However, without the exact bond energies values provided, we cannot complete the calculation. Methodologically, we would sum the energies of the bonds in the reactants to obtain the energy input and then sum the energies of the bonds in the products to obtain the energy released. The difference between these sums gives us the enthalpy change for the reaction.

The approximate enthalpy change will be in the range of the options provided (a, b, c, or d), with the recognition that bond energy calculations can only provide an approximation and have an uncertainty of roughly ± 50 kJ/mol.

User Juventus
by
7.7k points