Question

Methanol can be formed by the following unbalanced equation below. What is the mass in grams of methanol that can be formed from 107 molecules of co? h₂(g) co(g) → ch₃oh(l).

Answer 1

To find the mass of methanol that can be formed from 107 molecules of CO, we need to balance the equation and use stoichiometry. The molar mass of CO is 28 g/mol and the molar mass of CH₃OH is 32 g/mol.

Step-by-step explanation:

The given unbalanced equation is:

H₂(g) + CO(g) → CH₃OH(l)

To find the mass of methanol that can be formed from 107 molecules of CO, we need to balance the equation first. The balanced equation is:

2H₂(g) + CO(g) → CH₃OH(l)

Now, we can use stoichiometry to calculate the mass of methanol. The molar mass of CO is 28 g/mol and the molar mass of CH₃OH is 32 g/mol. Using the balanced equation:

1 mol CO = 32 g CH₃OH

Thus, 107 molecules of CO (which is equivalent to 107/6.022 x 10^23 moles) would produce:

(107/6.022 x 10^23) mol CO = [(107/6.022 x 10^23) mol CO] x (32g CH₃OH/1 mol CO)

Solving this equation will give you the mass of methanol in grams.