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Mary sold 20 necklaces and bracelets at a festival. She sold 3 times as many bracelets as necklaces. Identify the number of necklaces and bracelets Mary sold.

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Final answer:

Mary sold 5 necklaces and 15 bracelets.

Step-by-step explanation:

To find the number of necklaces and bracelets sold by Mary, we can set up a system of equations based on the given information. Let's let 'x' represent the number of necklaces and 'y' represent the number of bracelets. We know that Mary sold a total of 20 necklaces and bracelets, so we can write the equation: x + y = 20. We also know that she sold 3 times as many bracelets as necklaces, so we can write the equation: y = 3x. Solving this system of equations, we can substitute the second equation into the first equation to get: x + 3x = 20. Combining like terms, we have 4x = 20. Dividing both sides by 4, we find that x = 5. Plugging this value back into the second equation, we can find y: y = 3(5) = 15. Therefore, Mary sold 5 necklaces and 15 bracelets.

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