32.1k views
1 vote
What is the equation of the line that passes through (-1,1) and (2,3)?

A. y = 2/3x + 5/3
B. y = -2/3x + 5/3
C. y = 2/3x - 5/3
D. y = -2/3x - 5/3

User Giftcv
by
7.5k points

1 Answer

4 votes

Final answer:

The equation of the line passing through the points (-1,1) and (2,3) is calculated by first finding the slope, which is 2/3, and then using the point-slope form to arrive at the equation y = 2/3x + 5/3, option A.

Step-by-step explanation:

To find the equation of the line that passes through the points (-1,1) and (2,3), you first need to calculate the slope (m). The slope can be found using the formula m = (y2 - y1) / (x2 - x1). Plugging in our points, we get m = (3 - 1) / (2 - (-1)) = 2 / 3.

With the slope, we can then use the point-slope form of a line, y - y1 = m(x - x1), substituting one of our points and the slope into the formula. Using the point (-1,1), the equation becomes y - 1 = (2/3)(x + 1). Now, we just need to simplify and write it in the y = mx + b form, which gives us y = (2/3)x + (2/3) + 1 or y = (2/3)x + 5/3. Therefore, the correct answer is A. y = 2/3x + 5/3.

User Pankaj Lahoti
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories