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Which values of 'a,' 'b,' and 'c' are required to express the equation (5 + x)(5 - x) = 7 in its general form, Ax^2 + Bx + C = 0?

A) A = 1; B = 0; C = -18
B) A = -1; B = 0; C = 25
C) A = 25; B = 0; C = -1
D) A = 1; B = 0; C = 18

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Final answer:

To express the equation (5 + x)(5 - x) = 7 in its general form, we need to expand and simplify the equation, which gives us -x^2 + 18 = 0. Therefore, the values of 'a,' 'b,' and 'c' for the general form of the equation are A = -1, B = 0, and C = 18.

Step-by-step explanation:

To express the equation (5 + x)(5 - x) = 7 in its general form, Ax^2 + Bx + C = 0, we need to expand and simplify the equation.

First, we multiply the binomials (5 + x) and (5 - x) using the distributive property, which gives us:

25 - x^2 = 7

Next, we rearrange the equation in the standard form of a quadratic equation, Ax^2 + Bx + C = 0, by subtracting 7 from both sides:

-x^2 + 25 - 7 = 0

-x^2 + 18 = 0

Therefore, the values of 'a,' 'b,' and 'c' for the general form of the equation are A = -1, B = 0, and C = 18.

User Tom Whittock
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