Question

A water cooler contained 5.2 liters of water. Some water was added until the cooler contained 22.1 liters of water. Write an equation to represent the problem and solve how many times as much water is there in the cooler now?

Options:
A) What is the equation representing the problem?
B) How many liters of water were added to the cooler?
C) How many times as much water is there in the cooler now compared to the initial amount?
D) What is the total capacity of the water cooler?

Answer 1

The equation representing the problem is V₂ - V₁ = 22.1 L - 5.2 L = 16.9 L. The amount of water added to the cooler is 16.9 L. The times as much water compared to the initial amount is V₂/V₁ = 22.1 L / 5.2 L ≈ 4.25.

Step-by-step explanation:

To solve for the number of liters, we subtract the initial amount of water from the final amount of water. The equation representing the problem is:

V₂ - V₁ = 22.1 L - 5.2 L = 16.9 L

To calculate how many liters of water were added to the cooler, we subtract the initial amount of water from the final amount of water. The equation representing this is:

V₂ - V₁ = 22.1 L - 5.2 L = 16.9 L

To find out how many times as much water is there in the cooler now compared to the initial amount, we divide the final amount of water by the initial amount of water. The equation representing this is:

V₂/V₁ = 22.1 L / 5.2 L ≈ 4.25

The total capacity of the water cooler is the same as the final amount of water. Therefore, the total capacity is 22.1 liters.