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Which of the following is the vertex of the parabola y = x^2 - 4x?

(A) (-2, 0)
(B) (0, -4)
(C) (2, 0)
(D) (-4, 0)

1 Answer

6 votes

Final answer:

The vertex of the parabola y = x^2 - 4x is at the point (2, -4), which is not listed in the options provided, indicating a possible typo in the question.

Step-by-step explanation:

The vertex of a parabola in the form y = ax^2 + bx + c can be found using the formula -b/(2a) for the x-coordinate, and then substituting this value into the equation to find the y-coordinate. In the given equation y = x^2 - 4x, the values of a and b are 1 and -4, respectively. Therefore, the vertex's x-coordinate is -(-4)/(2*1) = 2. Substituting x = 2 back into the equation gives y = (2)^2 - 4(2) = 4 - 8 = -4, so the vertex is at the point (2, -4), which is not one of the options provided. It seems there may be a typo in the options, as none of them match the correct vertex.

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