Question

A 79.9 cm^3 sample of oxygen is collected by water displacement at 24°C. What volume would the gas occupy at standard pressure if the gas was collected originally at a pressure of 98.5 kPa?

Answer 1

To find the volume of the gas at standard pressure, use the combined gas law equation and convert the initial pressure to atm. The volume of the gas would be approximately 73.62 cm^3 at standard pressure.

Step-by-step explanation:

To determine the volume of the gas at standard pressure, we can use the combined gas law equation P1V1/T1 = P2V2/T2, where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2 and T2 are the final pressure and temperature.

First, we need to convert the initial pressure from kPa to atm by dividing it by 101.325. Then, we substitute the values into the equation:

(98.5 kPa / 101.325) * (79.9 cm^3 / (24 + 273.15) K) = V2 / (0°C + 273.15 K)

Solving for V2, we find that the volume of the gas would be approximately 73.62 cm^3 at standard pressure.