Final answer:
To make 3.2 L of 2.00 M nitric acid from 15.9 M nitric acid, you will need 0.402 L of the 15.9 M nitric acid.
Step-by-step explanation:
To calculate the volume of 15.9 M nitric acid required to make 3.2 L of 2.00 M nitric acid, we can use the equation:
(M1)(V1) = (M2)(V2)
Where M1 and V1 are the molarity and volume of the stock solution, and M2 and V2 are the desired molarity and volume of the final solution.
Given:
M1 = 15.9 M
V2 = 3.2 L
M2 = 2.00 M
Substituting these values into the equation:
(15.9 M)(V1) = (2.00 M)(3.2 L)
Solving for V1:
V1 = (2.00 M)(3.2 L) / 15.9 M = 0.402 L
Therefore, 0.402 L of the 15.9 M Nitric acid is required to make 3.2 L of 2.00 M nitric acid.