Question

"h(x) = -16t² + 35t + 0"

Answer 1

The quadratic equation h(x) = -16t² + 35t + 0 can be solved using the quadratic formula. The solutions for t are approximately 4.59 and -0.59.

Step-by-step explanation:

This expression is a quadratic equation of the form at² + bt + c = 0, where the constants are a = -16, b = 35, and c = 0. Its solutions are given by the quadratic formula:

`t = (-b \± √(b^2- 4ac) )) / (2a)`

Substituting the values of a, b, and c into the formula, we get:

`t = (-35 \± √(35^2 - 4(-16)(0))) / (2(-16))`

Simplifying further, we have:

`t = (-35 \±√(1225) ) / (-32)`

The two possible values of t are:

t ≈ 4.59 (approx. value)

t ≈ -0.59 (approx. value)

Therefore, the solutions to the quadratic equation h(x) = -16t² + 35t + 0 are t ≈ 4.59 and t ≈ -0.59.