Final answer:
Jose can only have 5 times as many pennies as nickels with a total of $0.20 in the combination of 10 pennies and 2 nickels according to the given options.
Step-by-step explanation:
Jose has a total of $0.20 worth of pennies and nickels. Each penny is worth $0.01, and each nickel is worth $0.05. Since Jose has 5 times as many pennies as nickels, we need to find combinations that fit this ratio and sum to $0.20.
- A penny is 1/100th of a dollar, and a nickel is 5/100th of a dollar.
- For every nickel that Jose has, he must have 5 pennies to maintain the 5:1 ratio.
- We can calculate the value of each combination to see if it adds up to $0.20.
Let's review the given options:
- A) 4 pennies, 1 nickel: This equals 4(pennies) × $0.01 + 1(nickel) × $0.05 = $0.09, which does not add up to $0.20 and does not meet the 5:1 ratio.
- B) 5 pennies, 1 nickel: This is correct by ratio and equals 5(pennies) × $0.01 + 1(nickel) × $0.05 = $0.10, which also does not add up to $0.20.
- C) 10 pennies, 2 nickels: This is correct by ratio and equals 10(pennies) × $0.01 + 2(nickels) × $0.05 = $0.20, which exactly adds up to $0.20. Therefore, option C is a correct combination.
- D) 2 pennies, 1 nickel: This equals 2(pennies) × $0.01 + 1(nickel) × $0.05 = $0.07, which does not add up to $0.20 and does not meet the 5:1 ratio.
From the above, the only correct combination that fits the condition of having 5 times as many pennies as nickels and adds up to a total of $0.20 is option C (10 pennies, 2 nickels).