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How many moles in 49.8 Liters of O, at STP?
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5 votes
How many moles in 49.8 Liters of O, at STP?

User Viku
by
5.5k points

1 Answer

9 votes

Answer:

2.22 mole

Step-by-step explanation:

At STP one mole of an ideal gas occupies 22.4 L of volume.

Hence,

Volume = mol × 22.4 L/mol

solving for mole,

Mole = Volume / 22.4 L/mol

Putting values,

Mole = 49.8 L / 22.4 L/mol

Mole = 2.22 mole

User Dylan Lawrence
by
4.3k points
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