Solve each equation.log_7 (x^2 + 11) = log_7 15 1) ±42) ±23) ±3.874) ±12

Frankusky asked May 13, 2023

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Frankusky asked May 13, 2023

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12 votes

Recall that:

$\log _ab=\log _ac\Leftrightarrow b=c.$

Therefore:

Subtracting 11 from the above equation we get:

$\begin{gathered} x^2+11-11=15-11, \\ x^2=4. \end{gathered}$

Therefore:

$x=\pm2.$

Answer: Second option.

Gagan Gami answered May 17, 2023

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