Question

F(x)=-2(x+3)(x+10)
smaller x=-10
larger x=-3
what is the vertex of the parabola?

Answer 1

The vertex of the parabola is approximately (0.00044, -60.00885).

Step-by-step explanation:

The vertex of a parabola can be found using the formula x = -b/2a, where a, b, and c are coefficients of the quadratic equation in the form ax^2 + bx + c. In this case, the quadratic equation is 0.000484 - 0.00088x + x^2 = 0. By comparing this equation with the standard form of a quadratic equation, we can find that a = 1, b = -0.00088, and c = 0.000484. Substituting these values into the formula, we get x = -(-0.00088)/(2*1) = 0.00044.

To find the y-coordinate of the vertex, we substitute x = 0.00044 into the given quadratic equation, f(x) = -2(x+3)(x+10). Evaluating f(0.00044), we get f(x) = -2(0.00044+3)(0.00044+10) = -2(3.00044)(10.00044) ≈ - 60.00885.

Therefore, the vertex of the parabola is approximately (0.00044, -60.00885).