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The solar panel heats 200kg of water each day. On one day, it increases the temperature of the water by 50 degrees. The specific heat capacity of water is 4200 J. Calculate the energy needed to increase the temperature of 200kg of water by 50 degrees.

Which indeed is the correct unit?

A) Joules

B) Seconds

C) Watts

User Gerry Coll
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Final answer:

To calculate the energy needed to increase the temperature of 200kg of water by 50 degrees, we can use the formula: Energy = mass x specific heat capacity x change in temperature. The correct unit for energy is Joules (J).

Step-by-step explanation:

To calculate the energy needed to increase the temperature of 200kg of water by 50 degrees, we can use the formula:

Energy = mass x specific heat capacity x change in temperature

Plugging in the values, we have:

Energy = 200kg x 4200 J/kg/°C x 50°C = 42,000,000 J

The correct unit for energy is Joules (J).

User Sreevalsa E
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