Final Answer:
The standard deviation of air conditioning unit repair time is approximately determined as the interval between 33 and 43 minutes, where 40% of units are repaired. Calculations, based on z-scores and the given percentiles, yield a standard deviation of approximately 5 minutes for the repair time distribution with a mean of 38 minutes.
Step-by-step explanation:
To find the standard deviation of repair time, we need to use the concept of z-scores in a standard normal distribution.
Let's denote the mean repair time as
minutes.
We know that 40% of the units are repaired between 33 and 43 minutes. This interval corresponds to the range
to
, where
is the standard deviation.
First, let's find the z-scores corresponding to the given percentiles in a standard normal distribution:
1. For the lower bound (33 minutes):
![\[ z_{\text{lower}} = (33 - \mu)/(\sigma) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/w4yvv9d51m5fxilng3arjbrvus90bb5d13.png)
2. For the upper bound (43 minutes):
![\[ z_{\text{upper}} = (43 - \mu)/(\sigma) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/mtus2cnijkiqezuc803zbaase35ediiqr1.png)
Now, we know that the area between these z-scores is 40%. Using a standard normal distribution table or calculator, we can find the z-scores that correspond to cumulative probabilities.
Let's assume
corresponds to the 20th percentile and
corresponds to the 60th percentile (since the area between them is 40%).
Now, we can solve for
using the z-scores:

Plug in the values and solve for
.

Substitute
and the values of
and
to find
. Once you find
, that will be the standard deviation of the repair time.