Final answer:
Carbon 6 contains an OH is the enantiomer of D‑arabinose.
The correct option is C.
Explanation:
The enantiomer of D-arabinose would have the opposite configuration at each chiral center compared to D-arabinose itself. D-arabinose is a pentose sugar with five carbon atoms in its backbone and an OH group on carbon 5 (not 6).
The OH group is positioned to the right side of carbons 3 and 4 in the Fischer projection of D-arabinose. Therefore, the correct statement about the enantiomer of D-arabinose is that carbon 6 contains an OH group in its structure.
So, the correct option is c. Carbon 6 contains an O H.
This question is incomplete, the complete question is:
Which structure is the enantiomer of D‑arabinose? a. A Fischer projection with a five carbon backbone. b. Carbon 1 contains an aldehyde. c. Carbon 6 contains an O H. d. The O H group is on the right of carbons 3 and 4.