273,666 views
22 votes
22 votes
Hello I need help I could figure this problems well.4 6/8 for the first one. so I said NO13/12 for the second one. so I said NO. 5 3/8 for the third one. so I said NO. I could not solve the last one.

Hello I need help I could figure this problems well.4 6/8 for the first one. so I-example-1
User Gaurab Kumar
by
2.7k points

1 Answer

20 votes
20 votes

Solution:

Given:


6(3)/(8)-1(5)/(8)

step 1: Express each mixed number as improper fractions.


\begin{gathered} 6(3)/(8)=((6*8)+3)/(8) \\ \Rightarrow(51)/(8) \\ 1(5)/(8)=((1*8)+5)/(8) \\ \Rightarrow(13)/(8) \end{gathered}

step 2: Find the difference between the fractions.


\begin{gathered} (51)/(8)-(13)/(8) \\ \text{LCM is 8} \\ \text{thus,} \\ =(51-13)/(8) \\ =(43)/(8) \end{gathered}

step 3: Expressed the obtained fraction as a mixed number.


(43)/(8)\Rightarrow5(3)/(8)

Since the result of the above operation is not equal to


4(3)/(4)

The correct choice is No.

Given:


(7)/(12)+2(1)/(3)+1(5)/(6)

step 1: Express each mixed number as improper fractions.


\begin{gathered} 2(1)/(3)=((2*3)+1)/(3)=(7)/(3) \\ 1(5)/(6)=((1*6)+5)/(6)=(11)/(6) \end{gathered}

step 2: Find the sum of the fractions.


\begin{gathered} (7)/(12)+(7)/(3)+(11)/(6) \\ \text{LCM is 12} \\ \text{thus,} \\ =(7+28+22)/(12) \\ =(57)/(12) \\ =(19)/(4) \end{gathered}

step 3: Expressed the obtained fraction as a mixed number.

Thus,


(19)/(4)\Rightarrow4(3)/(4)

Since the result of the above operation is


4(3)/(4)

The correct choice is Yes.

User Mark Miller
by
2.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.