Final answer:
The current when 2.00×10¹² electrons pass a point in 0.500 seconds is 6.408×10¹¹ amps, calculated using the charge of an electron and the formula for current I = Q/t.
Step-by-step explanation:
The question asks what the current in amps is when 2.00×10¹² electrons pass a point in a wire in 0.500 seconds. To find the current, we need to use the formula I = Q/t, where I is the current in amperes, Q is the total charge in coulombs, and t is the time in seconds that it takes for the charge to pass a point. The charge of a single electron is approximately 1.602×10¹¹³ C. First, we calculate the total charge by multiplying the number of electrons by the charge of a single electron: Q = (2.00×10¹² electrons) × (1.602×10¹¹³ C/electron) = 3.204×10¹¹ C. Then we calculate the current by dividing the total charge by the time: I = Q/t = (3.204×10¹¹ C) / (0.500 s) = 6.408×10¹¹ A. Hence, the current in the wire is 6.408×10¹¹ amps.