95.7k views
0 votes
Where is the following function discontinuous? f(x)=(x+3)/(x²+5x-24)

User Spenhouet
by
8.3k points

1 Answer

4 votes

Final answer:

The function f(x) = (x+3)/(x²+5x-24) is discontinuous at x = 3 and x = -8.

Step-by-step explanation:

The function f(x) = (x+3)/(x²+5x-24) is discontinuous at any value of x where the denominator is equal to zero. Therefore, to find where the function is discontinuous, we need to find the values of x that make the denominator zero.

First, let's factor the denominator. The quadratic equation x²+5x-24=0 can be factored as (x-3)(x+8)=0. This means that the denominator is equal to zero when x=3 or x=-8.

Therefore, the function f(x) is discontinuous at x=3 and x=-8.

User Evgeny Goldin
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories